16x^(2/3)-4x^(1/3)-2=0

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Solution for 16x^(2/3)-4x^(1/3)-2=0 equation: 


x in (-oo:+oo)

16*x^(2/3)-(4*x^(1/3))-2 = 0

16*x^(2/3)-4*x^(1/3)-2 = 0

t_1 = x^(1/3)

16*t_1^2-4*t_1^1-2 = 0

16*t_1^2-4*t_1-2 = 0

DELTA = (-4)^2-(-2*4*16)

DELTA = 144

DELTA > 0

t_1 = (144^(1/2)+4)/(2*16) or t_1 = (4-144^(1/2))/(2*16)

t_1 = 1/2 or t_1 = -1/4

t_1 = -1/4

x^(1/3)+1/4 = 0

1*x^(1/3) = -1/4 // : 1

x^(1/3) = -1/4

( -1/4 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 1/2

x^(1/3)-1/2 = 0

1*x^(1/3) = 1/2 // : 1

x^(1/3) = 1/2

x^(1/3) = 1/2 // ^ 3

x = 1/8

x = 1/8

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